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Mod time error for file older than one year File older than one year should be in "MMM DD YYYY" format, not "MMM DD hh:mm" format Reviewed-on: #150 Reviewed-by: Lunny Xiao <xiaolunwen@gmail.com> Co-authored-by: hpo3 <hpo3@noreply.gitea.io> Co-committed-by: hpo3 <hpo3@noreply.gitea.io>
55 lines
1.4 KiB
Go
55 lines
1.4 KiB
Go
// Copyright 2018 The goftp Authors. All rights reserved.
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// Use of this source code is governed by a MIT-style
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// license that can be found in the LICENSE file.
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package server
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import (
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"bytes"
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"fmt"
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"strconv"
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"strings"
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"time"
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)
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type listFormatter []FileInfo
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// Short returns a string that lists the collection of files by name only,
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// one per line
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func (formatter listFormatter) Short() []byte {
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var buf bytes.Buffer
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for _, file := range formatter {
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fmt.Fprintf(&buf, "%s\r\n", file.Name())
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}
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return buf.Bytes()
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}
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// Detailed returns a string that lists the collection of files with extra
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// detail, one per line
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func (formatter listFormatter) Detailed() []byte {
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var buf bytes.Buffer
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for _, file := range formatter {
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fmt.Fprint(&buf, file.Mode().String())
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fmt.Fprintf(&buf, " 1 %s %s ", file.Owner(), file.Group())
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fmt.Fprint(&buf, lpad(strconv.FormatInt(file.Size(), 10), 12))
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if file.ModTime().Before(time.Now().AddDate(-1, 0, 0)) {
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fmt.Fprint(&buf, file.ModTime().Format(" Jan _2 2006 "))
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} else{
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fmt.Fprint(&buf, file.ModTime().Format(" Jan _2 15:04 "))
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}
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fmt.Fprintf(&buf, "%s\r\n", file.Name())
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}
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return buf.Bytes()
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}
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func lpad(input string, length int) (result string) {
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if len(input) < length {
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result = strings.Repeat(" ", length-len(input)) + input
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} else if len(input) == length {
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result = input
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} else {
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result = input[0:length]
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}
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return
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}
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